An object of mass 2 kg is suspended from a spring of spring constant 500 N m–1. If the natural length of the spring is 10 cm, what is the length of the spring when the body is suspended?
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Answer:
by 2 cm/kg. If the spring is stretched and released, its time period will be: ... The spring constant can be found out by k=2cm1kg=0.02m10N=500N/m.
Explanation:
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