Question

An object of mass 2 kg is whirled round in a vertical circle of radius 1 m
with a constant speed of 4 msl. The maximum tension in the string is
(g = 10 ms)​

Answer 1

Answer:

T=mg +mv²/r

Explanation:

as it is moving with a constant velocity then acceleration is 0.

Answer 2

Answer:

Maximum tension on string = 52 N

Explanation:

Given, mass of object,m\ = 2 kg

Radius of circle,r = 1 m

speed of object on circular path = 4 $\dfrac{m}{s}$

and acceleration due to gravity = 10 $\dfrac{m}{s^2}$

Since, the object is moving on a vertical circular path so, the maximum tension on the string is when the body will be on its lowest position because at that point force due to gravity and centrifugal force both will act on the body in same direction.

So, maximum tension in spring = force due to gravity + centrifugal force

                                                  $=\ m.g\ +\ \dfrac{m.v^2}{r}$

                                                 $=\ 2\times 10\ +\ \dfrac{2\times 4^2}{1}$

                                                    = 52 N

So, the maximum tension on the string will be 52 N.