Question

An object of mass 2 kg moving with a velocity
of 5 km/s collides and sticks to a stationary
wooden block of
mass 5kg. They
both Move off
together. Calculate the speed of the
combined object.​

Answer 1

The speed of the combined object is V = 1.428 m/s.

- Given:

Mass of object, m1 = 2kg

Velocity of object before collision, u1 = 5 m/s

Mass of wooden block, m2 = 5 kg

Velocity of wooden block before collision, u2 = 0 (at rest)

- According to the law of conservation of momentum :

Total momentum before the collision = Total momentum after the collision

m1u1 + m2u2 = (m1 + m2) x V

2 x 5 + 5 x 0 = (2 + 5) x V

V = 10 / 7 = 1.428 m/s