Question

An object of mass 2 kg moving with a velocity v metre per second collides and sticks to a stationary wooden block of 5 kg mass they both move together calculate the speed of the combinend object

Answer 1

Answer:

v2 = 2/7v by law of conservation of linear momentum.

Answer 2

Solution :

⏭ Given:

✏ Mass of object = 2kg

✏ Initial velocity of object = v m/s

✏ Mass of block = 5kg

✏ Initial velocity of block = 0

⏭ To Find:

✏ Velocity of the combination after collision between moving object and stationary block.

⏭ Concept:

✏ In any type of collision, linear monentum of system is conserved.

⏭ Calculation

$\rightarrow \sf \: \blue{initial \: momentum = final \: momentum} \\ \\ \rightarrow \sf \: m_1u_1 + m_2u_2 = (m_1 + m_2)v \\ \\ \rightarrow \sf \: (2 \times v) + (5 \times 0) = (2 + 5)v' \\ \\ \rightarrow \sf \: 2v + 0 = 7v' \\ \\ \rightarrow \boxed{ \sf{ \red{v' = \frac{2v}{7}\:m/s}}} \: \star$