Question

An object of mass 2 kg travelling in straight line with a velocity of 10ms-1 collides with and

sticks to a stationary wooden block of mass 10 kg. Then they both move off together in same

straight line. Calculate the velocity of the combined object.​

Answer 1

Explanation:

Given,

m=1kg,u

1

=10ms

−1

,M=5kgandu

2

=0ms

−1

From conservation of momentum

Initial momentum = final momentum

mu

1

+Mu

2

=(m+M)v

1×10+5×0=(1+5)v

10=6v

Hence, velocity of both isv=

3

5

ms

−1

Total momentum before is 10kgms

−1

From momentum conservation, total momentum after is 10kgms

−1

please.........

Mark brainliest