an object of mass 2 kh at rest at origin starts moving
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Answer:
The velocity is (4î + 4j^)m/s.
Explanation:
Given data
M=2kg
F=(3t²î + 4tj^)N
we know that F=ma
=m dt/dv
[∵a= dt/dd ]
integrating on both side
∫Fdt=m∫du
∫Fdt=mv
∫(3t²î + 4tj^)dt = 2v
3t³î/3 + (4t²/2) j = 2v
t³î + 2t²j = 2v
substituting t22
8i + 8j = 2v
Therefore,
v = (4î + 4j^)m/s
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