Question

An object of mass 20 g moving with a velocity of 20 m/s comes to rest in 10 s. Calculate the force exerted on the object to stop it.

Answer 1

Answer:

40N

Explanation:

The mass of the object is (m) = 20g

initial velocity (u)= 20m/s

final velocity (v) = 0m/s

∆t= 10s

Now,

acceleration of the body (a) = (v-u)/∆t

= -2ms²(deceleration)

Thus , force required to stop the object

= ma = (20×2)N = 40N