An object of mass 20 kg and velocity of 20m/s from rest in 5 sec . Find the force applied on it in newton and dyne
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The problem with this question is that it does not specify the direction of the force relative to the particle’s initial velocity. For now, I will leave the direction open and give two answers depending on that.
We know the magnitude of the acceleration experienced by the body:
a=F/m=10m/s2a=F/m=10m/s2
in magnitude.
Note that
V−V0=at,V−V0=at,
with V0V0 the initial velocity.
Also
V2−V20=2ad,V2−V02=2ad,
with dd the net displacement of the body, and aaitself carries a sign depending on your coordinates and the direction of the acceleration. I will assume the displacement is in the positive direction of my coordinates, and the acceleration being either positive or negative depending on the (yet unspecified) direction of the force.
Note also that
V2−V20=(V+V0)(V−V0).
We know the magnitude of the acceleration experienced by the body:
a=F/m=10m/s2a=F/m=10m/s2
in magnitude.
Note that
V−V0=at,V−V0=at,
with V0V0 the initial velocity.
Also
V2−V20=2ad,V2−V02=2ad,
with dd the net displacement of the body, and aaitself carries a sign depending on your coordinates and the direction of the acceleration. I will assume the displacement is in the positive direction of my coordinates, and the acceleration being either positive or negative depending on the (yet unspecified) direction of the force.
Note also that
V2−V20=(V+V0)(V−V0).
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