Question

An object of mass 20 kg changes its velocity 6 ms^ 1 to 16 ms^1 in 5 sec. Find Force and distance covered?

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Answer 1

Explanation:

Initial velocity     u=5  m/s

                      Final velocity     v=2  m/s

The work done is equal to the change in the kinetic energy of an object.

W=21m(v2−u2)

W=21×20×(22−52)

⟹W=−210 J

Answer 2

Answer:

Precipitation is any liquid or frozen water that forms in the atmosphere and falls back to the Earth. It comes in many forms, like rain, sleet, and snow. ... Precipitation forms in the clouds when water vapor condenses into bigger and bigger droplets of water. When the drops are heavy enough, they fall to the Earth.

Work is said to be done when a force applied to an object moves that object. Work done is generally referred to in relation to the force applied while energy is used in reference to other factors such as heat.

Kinetic energy is given by the expression,

(K. E)v = 1/2 mv2

Where,

K. E = Kinetic energy of the object

v = velocity of the object

 Kinetic energy when the object was moving with a velocity of 5 m/s

(K. E)5 = 1/2 × 20 × (5)2

(K. E)5 = 250 J

Kinetic energy when the object was moving with a velocity 2 m/s

(K. E)2 = 1 /2 × 20 × (2)2

(K. E)2 = 40 J

Work done = Change in kinetic energy

= 40 J – 250 J

= – 210 J

Therefore, work done = -210 J