An object of mass 20 kg is dropped from a height of 4 m. Fill in the blanks in the following table by computing the potential energy and kinetic energy in each case. For simplifying
the calculations, take the value of g as 10 ms^-2. The total mechanical energy of the object remains _______.
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P.E = mgh
= 20×4×10
= 800J
K.E= 1/2 mv²
= 1/2 ×20×0
=0J
total mechanical energy =K.E + P.E
= 0+800
=800j
take height as 3m 2m and 1m mechanical energy will be constant i.e 800j
so total mechanical energy of an object remains 800j
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