an object of mass 20 kg is dropped from a height of 4 metre. fill in the blanks in the following table by computing the potential energy and kinetic energy in each case. for simplifying the calculation take the value of g as 10 metre per second square... and remember it should not answer should not be pasted from anywhere ❎no spamming❎ otherwise I will report you ✔️✔️✔️✔️✔️✔️
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Believe me it is correct!!
Potential energy is always greater than kinetic energy.
when h = 1m
Ep = mgh = 200j
Ek = mv2/2 = 193.6j
Ek+Ep = 200+193.6
= 393.6j
when h = 2m
Ep = mgh = 400j
Ek = mv2/2 = 396.9j
Ek+Ep= 400 + 396.9
= 796.9j
when h = 3m
mEp = mgh = 600
Ek = mv2/2 = 592.9j
Ek+Ep = 600 + 592.9
=1192.8j
when h = 4m
Ep = mgh = 800j
Ek = mv2/2 = 792.1j
Ek+Ep = 800 + 792.1
= 1592.1j
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