Question

An object of mass 20 kg moving with 50 m/s and comes to rest after 10 sec . Find the force of friction applied on the object ​

Answer 1

Answer:

Force of friction = -100N

Explanation:

u= 50 m/s

v= 0

m= 20 kg

t = 10 sec.

a= (v-u)/t

= (0-50)/10

= -5 m/ s²

Force of friction = ma

= 20×(-5)

= -100N

Negative sign depicts that it is applied in the opposite direction of the object.

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