an object of mass 200 kg is accelerated uniformly from a velocity of 5ms to 15ms in 5s. Calculate the charge in momentum of the object and find the force acting on it
Answers
Provided that:
- Mass = 200 kg
- Initial velocity = 5 mps
- Final velocity = 15 mps
- Time = 5 seconds
To determine:
- Change in momentum
- Force
Solution:
• Change in momentum = 2000 kg m/s
• Force = 400 N
Using concepts:
- ∆p formula
- Force formula
Using formulas:
- ∆p = m(v-u)
- F = m(v-u)/t
Where, ∆p denotes change in momentum, v denotes final velocity, u denotes initial velocity, t denotes time taken and m denotes mass.
Required solution:
~ Firstly let us find out the initial momentum by using suitable formula!
→ p = mu
→ p = 200(5)
→ p = 1000 kg m/s
→ Initial momentum = 1000 kg m/s
~ Now let us find out the final momentum by using suitable formula!
→ p′ = mv
→ p′ = 200(15)
→ p′ = 3000 kg m/s
→ Final momentum = 3000 kg m/s
~ Now let us calculate the change in momentum by using suitable formula!
→ ∆p = p′ - p
→ ∆p = mv - mu
→ ∆p = m(v-u)
→ ∆p = 200(15-5)
→ ∆p = 200(10)
→ ∆p = 2000 kg m/s
→ Change in momentum = 2000 kg m/s
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
~ Now let us find out the force by using suitable formula!
→ F = m(v-u)/t
→ F = 200(15-5)/5
→ F = 200(10)/5
→ F = 2000/5
→ F = 400 N
→ Force = 400 Newton