Question

An object of mass 200 kg is accelerated uniformly from a velocity of 5 ms–1 to 15 ms–1 in 5 s. Calculate the change in the momentum of the object and also find the force acting on it.
plz help​

Answer 1

Answer:

Change in momentum of the object = 2000 kg m s^-1.

The force acting on the object = 400 kg m s^-2

Explanation:

Formula: ΔP = m(v - u)

m = 200 kg

v = 15 m s^-1

u = 5 m s^-1

ΔP = m(v - u)

     = 200(15 - 5)

     = 200 x 10

     = 2000 kg m s^-1

∴ Change in momentum of the object = 2000 kg m s^-1.

∴ m(v - u) = 2000 kg m s^-1    ------> eq.1

Formula: F = ma

t = 5 s

F = ma

  = m x (v - u)/t

  = 2000/t                              (From eq.1)

  = 2000/5

  = 400 kg m s^-2

∴ The force acting on the object = 400 kg m s^-2

Answer 2

Answer:

400 kg

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