Question

An object of mass 200kg is accelerated uniformly from a velocity of 4m/s to 8m/s in 2 seconds. What is the formula for Impulse?

Answer 1

Answer:

1. v=u+at. is the answer bro

Answer 2

$\sf\large{\underline{\underline{Given:}}}$

$\sf\large{ \: \: \: Mass\:of\: the\:given\:object =200\:kg}$

$\sf\large{ \: \: \: Initial \:Velocity = 4\:m\:per\:sec}$

$\sf\large{ \: \: \: Final\:Velocity = 8\:m\:per\:second}$

$\sf\large{ \: \: \: Time\:duration = 2 sec}$

$\sf\large{\underline{\underline{Now:}}}$

$\sf\large{ \: \: \: Initial\:Momentum = 200\:kg × 4\:m\:per\:sec}$$\sf\large{ \: \: \: = 800\:kg\:m\:per\:sec}$

$\sf\large{ \: \: \: Final\:momentum = 200\:kg × 8\:m\:per\:sec}$$\sf\large{ \: \: \: = 1600\:kg\:m\:per\:sec}$

$\sf\large{\underline{\underline{So:}}}$

$\sf\large{ \: \: \: Change\:in\:momentum = 1600 - 800}$$\sf\large{ \: \: \: = 800\:kg\:m\:per\:sec}$

$\sf\large{\underline{\underline{ We\:know\:that:}}}$

$\sf\large{Force\:exerted = \dfrac{Change\:in\:momentum}{Time}}$

$\sf\large{ \: \: \: = \dfrac{800\:kg\:m\:per\:sec}{2\:sec}}$

$\sf\large{ \: \: \: = 400\:kg\:m\:per\: {sec}^{2}}$

$\sf\large{ \: \: \: = 400\:N}$

$\sf\large{\underline{\underline{Therefore:}}}$

$\sf\large{ \: \: \: Force\:exerted = 400N}$

$\sf\large{\underline{\underline{Formula\:for\:Impulse:}}}$

$\large{\bold{\fbox{\color{red}{ Change\:in\:Momentum= Applied\:Force × Elapsed\:Time}}}}$