An object of mass 200Kg is accelerated uniformly from a velocity of 8m per second to 12m per second in 10 second calculate the magnitude of force exerted on the object
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Mass of object, m=100kg; initial velocity, u=5ms
−1
; final velocity, v=8ms
−1
; time, t=6s
Initial momentum =mu=100×5=500Ns
Final momentum =mv=100×8=800Ns
Force exerted on the object
F=
t
mv−mu
=
6
800−500
=
6
300
=50N
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