Question

an object of mass 20kg after thrown up the body and object reach at 7 cm per hour from the initial position then calculate the work done by the object​

Answer 1

Answer:

40J

Explanation:

Correct option is

B

40J

K.E=

2

1

×m×v

2

K.E=0.5×0.2×20×20=40J

As it has 40 J at initial point as total energy, at some point X,P.E is maximum.

Total energy=P.E+K.E

40=P.E+K.E

As energy is conserved, total energy at point X also must be 40 J. For P.E to be maximum K.E must be zero.

Hence P.E=40J

We can come to the conclusion that it will have the maximum value at maximum height.