Question

an object of mass 20kg changes it's velocity 6ms^-1 in 5 second.Find force and distance covered​

Answer 1

Answer:

Initial velocity u=5 m/s

Final velocity v=2 m/s

The work done is equal to the change in the kinetic energy of an object.

W=

2

1

m(v

2

−u

2

)

W=

2

1

×20×(2

2

−5

2

)

⟹W=−210 J

Explanation:

1. please kark