An object of mass '25" "m//s' is moving with a velocity of '20" "s' . A force is applied so that in '10" "m//s' , it attains a velocity of '5" "kg' . What is the force applied on the object?
Answers
Appropriate Question:
An object of mass 5 kg is moving with a velocity of 10 m/s. A force is applied so that in 20s, it attains a velocity of 25m/s . What is the force applied on the object?
Answer:
3.75 N
Explanation:
As per the provided information in the given question, we have :
• Mass of the object (m) = 5 kg
• Initial velocity (u) = 10 m/s
• Time taken (t) = 20 seconds
• Final velocity (v) = 25 m/s
We have to calculate the force applied on the object.
In order to calculate the force applied on the object, firstly we need to calculate the acceleration here.
Acceleration is nothing the but the rate of change in velocity. So,
⇒ Acceleration = Change in velocity ÷ Time
⇒ Acceleration = ∆v/t
⇒ a = (v – u)/t
- a denotes acceleration
- u denotes initial velocity
- v denotes final velocity
- t denotes time
⇒ a = (25 - 10)/20
⇒ a = 15/20
⇒ a = 0.75 m/s²⠀⠀⠀⠀⠀⠀… ( 1 )
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Now, we'll find the force applied. According to the Newton's second law of motion,
⇒ F = ma
- F denotes force
- m denotes mass
- a denotes acceleration
Substitute the value of mass from the given data and the value of acceleration from ( 1 ).
⇒ F = 5 kg × 0.75 m/s²
⇒ F = 3.75 kg.m/s²
⇒ F = 3.75 N
∴ The force applied on the object is 3.75 N.