Question

an object of mass 250 kg is accelerated uniformly from a velocity of 15ms-¹ to 25ms-¹ in 5s calculate the magnitude of the force exerted on the object
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Answer 1

Given :-

• Mass (m) = 250kg
• Initial velocity (u) = 15ms-¹
• Final velocity (v) = 25ms-¹
• Time (t) = 5sec

To Find :-

• The force(F) exerted on the object.

Solution :-

As we know that,

${\boxed{\sf{a = \frac{v - u}{t}} }}$

[ Putting values ]

$↪ \sf \: a = \frac{25 - 15}{5}$

$↪ \sf \: a = \frac{10}{5}$

$↪ \sf \: a = 2ms {}^{ - 1}$

Now, we know that,

$↪ { \boxed{ \sf{F= ma}}}$

[ Putting values ]

$↪ \sf \: F = 250 \times 2$

$↪ \sf \: F = 500N$

Hence,

• The force exerted on the object is 500N.