Question

An object of mass 2kg is accelerated uniformly from a velocity of 2m/s to 4m/s in 2 seconds. The magnitude of the force acting on the object is

Answer 1

Answer:-

Given:-

• Mass (m) of the object = 2 kg
• Initial velocity (u) = 2 m/s
• Final velocity (v) = 4 m/s
• Time taken (t) = 2 s

To Find:-

Magnitude of force acting on the object.

_____________...

We know,

F = ma

where,

• F = Force,
• m = Mass of the object &
• a = Acceleration.

Also,

a = (v - u)/t

where,

• a = Acceleration,
• v = Final Velocity,
• u = Initial Velocity &
• t = Time taken.

So, we can also write:-

F = m[(v - u)/t]

= (2 kg)[(4 m/s - 2 m/s)/2 s]

= (2 kg)[(2 m/s)/2s]

= (2 kg)(1 m/s²)

= 2 kg m/s²

= 2 N

➽ Force acting of the body was 2 N.