Question

An object of mass 2kg is dropped from a height of 10 m. If the acceleration of sphere is 9.8 ms-2, calculate the momentum transferred to the ground by the ball.

Answer 1

Answer:

392

=∆p

Explanation:

m=2kg

a=-9.8

h=10

v^2=u^2+2as

v^2=0+2*-9.8*-10

v^2=196

v=14

momentum is:

mv=p

2*14=p

28=p