An object of mass 2kg is dropped from a height of 20m and rebound s to a height of 10m. What is its maximum kinetic energy during its upward in motion.
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2
Answer:
K.E = 196.0J
Explanation:
KE = 1/2MV² ⇒⇒⇒ equation 1
V² = U² +2gS ⇒⇒⇒ equation 2
V = final velocity = ?
U = initial velocity = 0
g = acceleration due to gravity = 9.8m/s²
S = displacement = 20 - 10 = 10m
substituting the values into equation 2 we get V = 14m/s
but we recall that K.E = 1/2mv²
m = 2.0kg
v = 14.0m/s
substituting these values into equation 1 we get
K.E = 1/2 × 2.0 × 14.0² = 196.0J
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Answer:
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Explanation:
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