an object of mass 2kg is moving with a velocity of 10m/s. find the momentum of the body. also calculate the value of the constant force which may reduce the velocity of the object to zero when applied on it up to a distance of 10m
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mass of object/m = 2kg
velocity /v= 10m/s
momentum = v.×m
10×2 = 20 kgm/s
for force you have to find acceleration and mass . Mass is available .
v sq - u sq = 2as
0-100= 2 a 10
a = -100/20 = -5m/s
force =m×a
=2 × -5
= -10N
velocity /v= 10m/s
momentum = v.×m
10×2 = 20 kgm/s
for force you have to find acceleration and mass . Mass is available .
v sq - u sq = 2as
0-100= 2 a 10
a = -100/20 = -5m/s
force =m×a
=2 × -5
= -10N
pinky817:
answer is 20kg-m/s,-10n
sry i would be -100 actuqlly
Answered by
3
m=2kg
v=10m/s
final momentum=mv
2×10
=20
initial momentum=0×10
=0
v=10m/s
final momentum=mv
2×10
=20
initial momentum=0×10
=0
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