Question

an object of mass 2kg placed on an inclined plane of 30 degree.if it takes 5 second to reach the ground then calculate final velocity​(assume no firiction)

Answer 1

Answer:

Given,

m=2kg

θ=30^o

μ=0.5

g=10m/s^ 2

The contact force is F

c is the resultant of frictional force and normal force.

From the free body diagram,

Normal force, N=mgcosθ

N=2×10×cos30^0

N=17.320N

The friction force, F

r =μmgcosθ

Fr =0.5×2××10×cos30^ 0

Fr =8.660N

N and Fr are perpendicular to each other.

The contact force is, F

c = N 2+Fr2

F

c= (17.320)2+(8.699) 2

F

c =19.381N

We can say approximately 20 N

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