an object of mass 2kg placed on an inclined plane of 30 degree.if it takes 5 second to reach the ground then calculate final velocity(assume no firiction)
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Answer:
Given,
m=2kg
θ=30^o
μ=0.5
g=10m/s^ 2
The contact force is F
c is the resultant of frictional force and normal force.
From the free body diagram,
Normal force, N=mgcosθ
N=2×10×cos30^0
N=17.320N
The friction force, F
r =μmgcosθ
Fr =0.5×2××10×cos30^ 0
Fr =8.660N
N and Fr are perpendicular to each other.
The contact force is, F
c = N 2+Fr2
F
c= (17.320)2+(8.699) 2
F
c =19.381N
We can say approximately 20 N
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