Question

an object of mass 2kg rotates at constant speed in a horizontal circle of radius 5m. the time for one complete revolution is 3sec . what is the magnitude of the resultant force acting on the object?

Answer 1

m = 5 kg

r = 5 m

F = mω²r

⇒ ω = 2π/T = 2π/3

On solving we get F = 40π²/9

Answer 2

Concept:

The entire force operating on the item or body, combined with the body's direction, is referred to as the resultant force.

Given:

The mass of an object is 2kg.

The object rotates in a horizontal circle of radius 5m.

The time taken to complete one revolution is 3 seconds.

Find:

The resultant force acting on the object.

Solution:

The force acting on an object in rotational motion can be given as:

F = mω²r

Now,

ω =  2π/T

The time period of one revolution is 3 sec, the radius is 5m and the mass of the object is 2kg.

Therefore, the resulting force is:

$F=(2)(5)(\frac{2\pi }{3})^2$

$F=\frac{40\pi^2 }{9}N$

The resultant force acting on the object is $\frac{40\pi^2 }{9}N$.

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