Question

An object of mass 3 kg and density 4500 kg/m3 is immersed in water. Find the mass of water displaced. ​

Answer 1

$\LARGE\underline{\underline{\sf Given:}}$

• Mass of object = 3kg

• Density of object = 4500kg/m³

$\LARGE\underline{\underline{\sf To\:Find:}}$

• Mass of water displaced = ?

$\LARGE\underline{\underline{\sf Solution:}}$

According to Archimedes' Principle :

${\boxed{\tt Mass\:of\: water\: displaced=Volume\:of\: object×Density\:of\:water }}$

Here ,

We know that :

$\large{\boxed{\tt \rho=\dfrac{Mass}{Volume} }}$

$\large\implies{\tt V=\dfrac{M}{\rho}}$

$\large\implies{\tt V=\dfrac{3}{4500}m^3}$

On Putting Value in given Formula

$\implies{\tt Water\:Disp.\:Mass=\dfrac{3}{4500}×1000 }$

$\implies{\tt \dfrac{2}{3} }$

$\implies{\tt 0.66kg }$

$\LARGE\underline{\underline{\sf Answer:}}$

•°• Mass of water displaced is 0.66g

Answer 2

Answer is 0.66g.

Given:

Mass of object = 3kg

Density of object = 4500kg/m³

To Find:

Mass of water displaced = ?

Solution:

According to Archimedes' Principle :

Mass of water displaced=Volumeofobject×Densityofwater

Here ,

We know that :

ρ=VolumeMass

⟹V=ρM

⟹V=45003m3

On Putting Value in given Formula

\implies

⟹Water Displaced

Mass=45003×1000

⟹32

⟹0.66kg

•°• Mass of water displaced is 0.66g

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