An object of mass 3 kg is at rest. Now a force
F = 6t2 i + 4t is applied on the object then
velocity of object at t = 3s is
(1) 181 +3] (2) 181 +6]
(3) 31 +18) (4) 189 +4)
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Answer:18i+6j
Explanation:given Ma =2t^2i+4/3tj
a=dv/dt
Int dv=int2t^2i+4/3j
V=18i+6j
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