Physics, asked by smarty1999, 9 months ago

An object of mass 3 kg is at rest. Now a force
F = 6t2 i + 4t is applied on the object then
velocity of object at t = 3s is
(1) 181 +3] (2) 181 +6]
(3) 31 +18) (4) 189 +4)

Answers

Answered by aneeshgv26

3

Answer:18i+6j

Explanation:given Ma =2t^2i+4/3tj

a=dv/dt

Int dv=int2t^2i+4/3j

V=18i+6j

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