Question

an object of mass 3 kg is thrown vertically upward with a velocity of 10 metre per second find the(i) kinetic energy of the body at the time of throwing (ii) its potential energy at the height​

Answer 1

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(i) Kinetic energy is the energy in an object due to its motion.

Kinetic energy is measured in joules.

Kinetic energy is the half of product of mass of a body and square of its velocity. Mathematically it is represented by :-

$\frac{1}{2} \times m {v}^{2}$

Now, it is given that :-

Mass of object = 3kg

Initial velocity of object = 10m/s

Kinetic energy = ?

Potential energy = ?

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Now, kinetic energy of object will be :

$= \frac{1}{2} \times 3 \times {10}^{2}$

$= 150j$

ii) Now at maximum height the final velocity of the object will become 0.

Now according to third equation of motion :

${v}^{2} = {u}^{2} + 2as$

Maximum height traveled by object will be:

$s = \frac{ {v}^{2} - {u}^{2} }{2a}$

After inputting the values in the equation we get:

$s \: = \frac{0 - 100}{ - 9.8}$

Here (-) before g shows the vertical direction

$s = \frac{ - 100}{ - 19.6}$

$= 5$

Now the distance or maximum height of object is 5m.

Thus the potential energy will be :

$3 \times 9.8 \times 5$

$= 147j$

______________________________________ BY√\__________ SCIVIBHANSHU

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Answer 2

Answer:

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Explanation:

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