an object of mass 3 kg is thrown with an velocity of 2 metre per second assuming velocity to be constant calculate kinetic energy when its hit a wall. what is force exerted on the ball to bring it to rest
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If an object whose mass is 20 kg is dropped from height of 10m, what is the maximum kinetic energy it will attain?
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Joe Rovito, I've thought about this stuff a lot. And read about it, too.
Updated Dec 20 · Author has 1.5k answers and 1.9m answer views
Although Kinetic Energy = 1/2 * m * v^2, you don't have to calculate the velocity directly to solve this problem.
The potential energy of an item is: m*g*h
m is mass in kg.
g is the acceleration due to gravity in m/s^2 (e.g. 9.81)
h is the height in meters
This yields 10*9.81*20 = 1962 kg*m^2/sec^2 (aka N*m or joules)
immediately before impact, 100 % of the potential energy has been converted to kinetic energy.
1962 Joules is my final answer.
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14 ANSWERS

Joe Rovito, I've thought about this stuff a lot. And read about it, too.
Updated Dec 20 · Author has 1.5k answers and 1.9m answer views
Although Kinetic Energy = 1/2 * m * v^2, you don't have to calculate the velocity directly to solve this problem.
The potential energy of an item is: m*g*h
m is mass in kg.
g is the acceleration due to gravity in m/s^2 (e.g. 9.81)
h is the height in meters
This yields 10*9.81*20 = 1962 kg*m^2/sec^2 (aka N*m or joules)
immediately before impact, 100 % of the potential energy has been converted to kinetic energy.
1962 Joules is my final answer.
plzz mark it brainliest
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