Question

An object of mass 3kg is at rest. now a force F=6t^2i^+4tj^ is applied on the object then velocity of the object at t=3sec will be?

Answer 1

if this helps you please mark it as brainliest.

Answer 2

Given that,

Mass of an object, m = 3 kg

Initial velocity, u = 0

Force, $F=6t^2i^+4tj$

To find,

The velocity of the object at t = 3 s.

Solution,

We know that,

Force, F = ma

$m\times \dfrac{v-u}{t}=6t^2+4t\\\\\dfrac{mv}{t}=6t^2+4t\\\\v=\dfrac{6t^3i+4t^2j}{m}$

Put t = 3 s and m = 3 kg

$v=\dfrac{6(3)^3i+4(3)^2j}{3}\\\\=\dfrac{162i}{3}+\dfrac{36j}{3}\\\\=(54i+12j)\ m/s$

So, the velocity of the object at t = 3 s will be (54i+12j) m/s.