An object of mass 3kg is at rest.Now a force Fvector=6t2icap+4tjcap is applied on the object then velocity of object at t=3s is
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F=m∗a
a=Fm
a=2t2i+2t3j
a=dvdt
dvdt=2t2i+0.66
tj
given initially at rest
∫v0dv=∫30(2t2i+0.66tj)dt
v=[1.33t3i+0.33t2]30
v=17.82i+2.97j
Taking resultant
v=17.822+2.972−−−−−−−−−−−√
v=18.065m/s
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