An object of mass 4 kg and density 2 x 10^3 kgm' is completely immersed in water, its
apparent weight will be
Answers
Answer:
2 kg wt
Explanation:
Hi friend! Hope this answer will help you!
Given-
Object mass= 4 kg
Density of object = 2*10^3 kg/m^3
Object is completely immersed in water.
To find-
Apparent weight of object!
What the question means exactly-
An object with certain mass and density is immersed in water. When an object is immersed in water the weight of the object becomes less. Because, buoyancy of the water is acting on the body pushing it upwards. And that weight is called as the apparent weight or fake weight. And we are asked to find that apparent weight.
We know that, apparent weight is less than the true weight as explained above. So, there is an net upward force in the body.
Formulae used-
W' = W ( 1- (1/RD) )
Solution-
Let's consider the weight of the object as = 4 kg wt
Apparent weight = W'
Relative density = 2*10^3 / 10^3 = density of body/ density of water!
= 2
Now we use the formulae!
W' = 4 ( 1 - 1/2 )
= 2
2 KG WT IS THE ANSWER!!
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