An object of mass 4 kg moving with velocity of 6 m/s along a straight line collides head on with another object of mass 2 kg which is at rest. If the collision is perfectly elastic what is the velocity of the first object after the collision?
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Answers
Answered by
1
Step-by-step explanation:
Linear momentum is conserved
0.4×4+0.4×2=0.8×v
as shown in figure and B.
v=
0.8
1.6+0.8
=3m/s
Kinetic energy before collision =
2
1
0.4(4)
2
+
2
1
0.4(2)
2
=3.2+0.8=4J
Kinetic after collision =
2
1
0.8(v)
2
=0.8×3
2
=3.6
Loss of kinetic energy =4−3.6=0.4J
Answered by
1
Answer:
Linear momentum is conserved
0.4×4+0.4×2=0.8×v
as shown in figure and B.
v=0.81.6+0.8=3m/s
Kinetic energy before collision =210.4(4)2+210.4(2)2
=3.2+0.8=4J
Kinetic after collision =210.8(v)2=0.8×32=3.6
Loss of kinetic energy =4−3.6=0.4J
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