Question

An object of mass 40 g has a volume of 20 cm3. Calculate the density of an object. If the density of water is 1 gcm-3, state whether the object will float or sink in water. Explain why.​

Answer 1

$\huge\red{\boxed{\mathcal{SOLUTION}}}$

We know that

Density =

$\frac{mass}{volume}$

Mass of the object = 40 g

Volume of the object = 20 cm3

∴ Density =

$\frac{40g}{20cm3}$

= 2 gcm-3

Therefore, the density of the object is 2 gcm-3.

An object will float in water if its density is less than that of water. Otherwise, it will sink. The given object will sink in water as its density (2 gcm-3) is more than that of water (1 gcm-3).

Answer 2

Answer:

We know that

Density =

mass by volume

Mass of the object = 40 g

Volume of the object = 20 cm3

∴ Density =

\frac{40g}{20cm3}20cm340g

= 2 gcm-3

Therefore, the density of the object is 2 gcm-3.

An object will float in water if its density is less than that of water. Otherwise, it will sink. The given object will sink in water as its density (2 gcm-3) is more than that of water (1 gcm-3

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