Question

An object of mass 40 kg and having velocity 4 m/s collides with another object of mass 60 kg,having velocity 2 m/s in the same direction. The loss of energy when the collision is perfectly inelastic is

(A) 392 J
(B) 440J
(C) 48 J
(D) 110J
​

Answer 1

Answer:

c. will be correct answers

Explanation:

Mark the answer brainliests please

Answer 2

$\sf \huge \fcolorbox{red}{pink}{Solution :)}$

Given ,

• Mass of first object is 40 kg and its velocity is 4 m/s
• Mass of second object is 60 kg and its velocity is 2 m/s

We know that , the loss of total kinetic energy (T) in perfectly inelastic collision is given by

$\large \sf \fbox{ΔT = \frac{1}{2} \times (\frac{ m_{1} \times m_{2} }{m_{1} + m_{2} } ){(u_{1} - u_{2} )}^{2} \: \: }$

Substitute the known values , we get

$\sf \hookrightarrow ΔT = \frac{1}{2} \times ( \frac{2400}{100}) \times {(2)}^{2} \\ \\ \sf \hookrightarrow ΔT = 24 \times 2 \\ \\ \sf \hookrightarrow ΔT = 48 \: \: joule$

Hence , The loss of total kinetic energy in perfectly inelastic collision is 48 J

______________ Keep Smiling ☺