Question

an object of mass 40 kg is acted upon by force of 20N for a time of 5 secs. Find the change of momentum of the object
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Answer 1

Answer:

20kg m/s

Explanation:

Force=∆p/t and ∆p=(v-u)m/t

Mass=40kg, (v-u)=? , Force= 20N and time=5s

20=40×(v-u)/5

(v-u)=20/8.

∆p=40×(v-u)/5

=8×20/8

=20kgm/s