Question

An object of mass 40 kg is raised to a height of 5 m above the ground. What is it's potential energy? If the object is allowed to fall, find its kinetic energy when it is half-way down.​

Answer 1

$\huge\mathfrak{Bonjour!!}$

$\huge\bold\purple{Answer:-}$

⏩ Here, m= 40 kg, g= 10 m s^-2, h= 5 m.

* Potential energy of the object at a height of 5 m,

Ep = mgh = 40 × 10 × 5 = 2000 J. Ans.

When the object is half-way down (s= 2.5 m), let it's velocity be 'v'. Then,

v² - u² = 2gs

→ v² - 0² = 2 × 10 × 2.5

or

v² = 50

Therefore,

Kinetic energy of the object,

Ek = 1/2 mv²

= 1/2 × 40 × 50 = 1000 J. Ans.

✔✔✔✔✔✔

Hope it helps..:-)

⭐♥✨❤⭐♥✨❤⭐

Be Brainly...✌✌✌

♣ WALKER ♠

Answer 2

Answer:

potential energy at 5m height=m.g.h=40.10.5=2000joule

potential energy at 2.5 m height= m.g.h

=40.10.2.5=1000j

means, left 1000(2000-1000) joule potential energy is converted in to kinetic energy

so, kinetic energy=1000 joule