Physics, asked by AKP828, 4 months ago

An object of mass 40 kg is raised to a height of 5 m above the ground. What is its potential energy? If the object is allowed to fall, find its kinetic energy when it is half way down.​

Answers

Answered by Ataraxia
14

Solution :-

\boxed{\bf Potential \ energy = mgh}

  • m = Mass
  • g = Acceleration due to gravity
  • h = Height

Here :-

  • m = 40 kg
  • g = 10 m/s²
  • h = 5 m

\longrightarrow \sf P.E = 40 \times 10 \times 5  \\\\\longrightarrow \bf P.E = 2000J

Potential energy = 2000J

When object is allowed to fall half way down :-

Height = 5/2 = 2.5 m

Initial velocity, u = 0 m/s

We can find final velocity (v) using third equation of kinematics.

\boxed{\bf v^2 - u^2 = 2gh}

\longrightarrow \sf v^2 - 0^2 = 2\times 10 \times 2.5 \\\\\longrightarrow v^2= 50 \\\\\longrightarrow \bf v= \sqrt{50}  \ m/s

\boxed{\bf Kinetic \ energy = \dfrac{1}{2} mv^2}

\longrightarrow \sf K.E = \dfrac{1}{2} \times 40 \times (\sqrt{50}  )^2 \\\\\longrightarrow K.E = \dfrac{1}{2} \times 40\times 50 \\\\\longrightarrow K.E = \dfrac{1}{2} \times 2000 \\\\\longrightarrow\bf K.E = 1000J

Kinetic energy of the object when it is allowed to fall half way down = 1000J

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