An object of mass 40 kg is raised to a height of 5 m above the ground. What is its potential energe Ifthe object is allowed to fall, find its kinetic energr when it is half-way down.
Answers
Answered by
0
Hi , there !!
potential energy = mgh
=> 40 kg × 5m × 10 { g = 10 }
2000 jule
Kinetic energy during half way
1/ 2 × 2 m v²
=> 1 / 4 × 40 × 5 × 5
=> 250 jule .
hope it helps you !!!
thanks !!
potential energy = mgh
=> 40 kg × 5m × 10 { g = 10 }
2000 jule
Kinetic energy during half way
1/ 2 × 2 m v²
=> 1 / 4 × 40 × 5 × 5
=> 250 jule .
hope it helps you !!!
thanks !!
Answered by
0
_/\_Hello mate__here is your answer--
_______________________
Given:-
m = 40 kg
g = 9.8 m/s^2
h = 5 m
We know that,
potential energy = mgh
= 40 × 9.8 × 5 J
= 1960 J
_______________________
♦♦The total mechanical energy (Kinetic and potential energy) of an object remains constant. (law of conservation of energy)
Therefore, when the object is half-way down, its potential energy become half the original energy and remaining half converted into kinetic energy.
Hence, the kinetic energy = ½ (1960) J = 980 J
I hope, this will help you.☺
Thank you______❤
_________________________❤
Similar questions