An object of mass 40 kg is raised to a height of 5 M what is its potential energy if the object is allowed to fall find its kinetic energy when it is Halfway down
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Answered by
1
hey dearie ..here is your answer...
P.E. at top =mgh
=40×5×9.8
=1960 J
P.E when half way down= mgh
=40×2.5×9.8
=980J
and we know that loose in potential energy is refers to an equal increase in the kinetic energy...So the kinetic energy also be 980J
P.E. at top =mgh
=40×5×9.8
=1960 J
P.E when half way down= mgh
=40×2.5×9.8
=980J
and we know that loose in potential energy is refers to an equal increase in the kinetic energy...So the kinetic energy also be 980J
Answered by
2
_/\_Hello mate__here is your answer--
_______________________
Given:-
m = 40 kg
g = 9.8 m/s^2
h = 5 m
We know that,
potential energy = mgh
= 40 × 9.8 × 5 J
= 1960 J
_______________________
♦♦The total mechanical energy (Kinetic and potential energy) of an object remains constant. (law of conservation of energy)
Therefore, when the object is half-way down, its potential energy become half the original energy and remaining half converted into kinetic energy.
Hence, the kinetic energy = ½ (1960) J = 980 J
I hope, this will help you.☺
Thank you______❤
_________________________❤
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