Question

An object of mass 40 kg is raised to a height of 500 cm above the ground. What is its potential energy? If the object is allowed to fall, find its kinetic energy when it is half way down. (g = 1000 cm/sec

Answer 1

p.e.=mgh=40×0.500×10=40×1/2×10
=200 j
half height =1/2×1/2=1/4m
p.e.=mgh=40×1/4×10
=100j
t.mechanical energy=k.e.+p.e.
200=p.e +100
p.e.=100

Answer 2

_/\_Hello mate__here is your answer--

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Given:-

m = 40 kg

g = 10 m/s^2

h = 5 m

We know that,

potential energy = mgh

= 40 × 10 × 5 J

= 2000 J

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♦♦The total mechanical energy (Kinetic and potential energy) of an object remains constant. (law of conservation of energy)

Therefore, when the object is half-way down, its potential energy become half the original energy and remaining half converted into kinetic energy.

Hence, the kinetic energy = ½ (2000) J = 1000 J

I hope, this will help you.☺

Thank you______❤

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