Question

An object of mass 40 kg moving along straight line with a horizontal velocity of 15 mper second collides and stick to a stationary wooden block of mass 10 kg. If the surface is smooth, the combined object after collision moves along the same straight line with a velocity of

Answer 1

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Answer 2

Answer:

Explanation:

Given,

• Mass of the first object = $m_1\ =\ 40\ kg$
• Mass of the second object = $m_2\ =\ 10\ kg$
• Initial speed of the first object = $v_1\ =\ 15\ m/s$.
• Initial speed of the second object = $v_2\ =\ 0\ m/s.$

First and second which is at rest collides with each other after the collision, they stick together, therefore the final speed of the both objects are same as of v after the collision,

From the conservation of linear momentum,

$m_1v_1\ +\ m_2v_2\ =\ (m_1\ +\ m_2)v\\\Rightarrow v\ =\ \dfrac{m_1v_1\ +\ m_2v_2}{m_1\ +\ m_2}\\\Rightarrow v\ =\ \dfrac{40\times 15\ +\ 0\ }{40\ +\ 10}\\\Rightarrow v\ =\ 12\ m/s.$

Hence the velocity of the both objects after the collision is 12 m/s.