Question

An object of mass 5 kg is acted upon by a force that varies with position of the object as shown. If the object starts out from rest at a point x = 0. What is its speed at x = 50m? ​

Answer 1

Answer:

a)12.2m/s

Explanation:

change in kinetic energy=work done

= Aera under F-x graph

1/2×m ×v²=10×25+1/2×25×10

1/2×5×v²=10×25+ 1/2×25×10

v²= 375×2/5

v²=150

v=√150

V=12.2m/s

Mark me brainlist it took a lot of effort