Question

An object of mass 5 kg is kept at rest. A force of 20 Newton acts on it for 5 seconds. Find the distance travelled by object in 10 seconds.

Answer 1

since

F = ma

a = F/M

a = 4m/s^2

s = ut + at^2/2

u = 0

t = 10s

s = 4*100/2=200m

Answer 2

Answer:

Explanation:

a= F/m

a=2/0.5=4m/s²

Distance covered in first 5 sec

s=ut +1/2at²

s=1/2*4*5²

s=50m

Now we will find distance covered in first 10 sec

s=1/2*4*10²

s=200m

Therefore, the distance travelled in next 5 sec is 200-50=150m