An object of mass 5 kg is moving with a constant velocity of 10 ms-1. A constant force acts on
it opposite to the velocity for 4 seconds and gives it a velocity of 2 ms-1 in the opposite
direction. Find the acceleration produced by the force
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Answer:
Change in velocity
−2−10=−12
Time required is 4 seconds
a=Δv/t
=−12/4
=−3m/s²
Hence,
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