Question

An object of mass 5 kg is moving with a velocity of 10 ms". A force is applied so that in
15 s, it attains a velocity of 25 ms"!. What is the force applied on the object?​

Answer 1

Question:-

An object of mass 5 kg is moving with a velocity of 10 ms". A force is applied so that in

15 s, it attains a velocity of 25 ms"!. What is the force applied on the object?

Answer:-

Force = mass × acceleration

Acceleration = $\frac{(change in velocity)}{time intervals}$

Initial velocity = 10m/s

Final velocity = 25m/s

Time intervals = 20s

Therefore,

Acceleration = (25 - 10)/20

= $\frac{0.75m}{s}^2$

Force = mass × acceleration

= 5 × 0.75

= 3.75N

Answer 2

Question:-

An object of mass 5 kg is moving with a velocity of 10 ms". A force is applied so that in

15 s, it attains a velocity of 25 ms"!. What is the force applied on the object?

Answer:-

Force = mass × acceleration

Acceleration = $\frac{(change\:in\: velocity)}{time\:intervals}$

Initial velocity = 10m/s

Final velocity = 25m/s

Time intervals = 20s

Therefore,

Acceleration = (25 - 10)/20

= $\frac{0.75m}{s}^2$

Force = mass × acceleration

= 5 × 0.75

= 3.75N