An object of mass 5 Kg is moving with a velocity of 20 m/s. What would be the work done to stop the moving object?
Answers
Answered by
0
Hey buddy here's ur answer....
we have,,, W = m×v^2
W= 5× (20)^2
W= 5× 400
W= 2000joules..
❤❤hope it helps
we have,,, W = m×v^2
W= 5× (20)^2
W= 5× 400
W= 2000joules..
❤❤hope it helps
Answered by
1
Given : m=5kg , v=20m/s , u = 0
Solution:
We know that,
Work done (W) = change in kinetic energy
W = 1/2mv^2 - 1/2mu^2
W = 1/2 x 5 x 20^2 - 0
W = 1/2 x 5 x 20 x 20
W = 1000 J.
Please mark my answer as Brainliest
Solution:
We know that,
Work done (W) = change in kinetic energy
W = 1/2mv^2 - 1/2mu^2
W = 1/2 x 5 x 20^2 - 0
W = 1/2 x 5 x 20 x 20
W = 1000 J.
Please mark my answer as Brainliest
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