Question

An object of mass 50 gm placed on a rough horizontal surface. The surface together with the block on it is performing simple harmonic motion along the horizontal

with a time period 0.5 sec. Coefficient of friction between
the block and the surface is 2/5 Maximum amplitude of SHM
such that the object does not slip along the surface is: g = 10 m/s²)

a. 6cm  
b.8.5cm
c. 2.5cm
d. 1.2cm

Answer 1

c.1.2 I think it just I don't no is it correct or not

Answer 2

The maximum amplitute of the object that does not slip along the surface is 2.5 cm

Step by Step Explanation:

Given: An object of mass is 50gm

Time period is 0.5 sec

Coefficient of friction is 2/5

To find: Maximum amplitude of the object

As we know that,

μ$mg =$ω$^{2} A_{max}$

Amax is the maximum amplitude

$A_{max} =$μg / ω$^{2}$

⇒ $\frac{x\frac{(2)(5)}{10} }{4\pi ^{2} }$

⇒ $\frac{4}{16\pi ^{2} } m$

Convert meter into centimeter

⇒ $\frac{100}{4\pi ^{2} } cm$

⇒ 2.5 cm

Final answer:

The maximum amplitude of SHM with the object does not slip along the surface is 2.5 cm

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