Question

an object of mass 50 gram is at rest on a smooth surface a force of 2 n act on it for 5 seconds calculate the distance travelled by the object​

Answer 1

500 m is the required answer.

GIVEN:

• Mass of the object, m = 50 g
• Force, f = 2 N
• Time , t = 5 seconds
• Since the object is initially at rest, its initial velocity is zero. u = 0

TO FIND:

Distance travelled by the object, s

FORMULAE:

To find distance travelled by the object, it is necessary to find the acceleration of the object.

Acceleration can be found using Newton's formula.

• According to Newton's second law of motion, f = ma

• According to the second equation of motion, s = ut +(at²)/2

SOLUTION:

STEP 1: To convert mass in standard unit.

• SI unit of mass is kilogram, kg

• 1 gram = 10^-3 kg

• 50 g = 50 × 10^-3 kg

• Mass, m = 5 × 10^-2 kg

STEP 2: To find acceleration

$f = ma \\\\ 2 = 5 \times {10}^{ - 2} \times a \\ \\ a = \dfrac{2}{5 \times {10}^{ - 2} } \\ \\ a = \dfrac{2}{5} \times {10}^{2} \\ \\ a = \dfrac{200}{5} \\ \\ a = 40 \: \dfrac{m}{ {s}^{2} }$

Acceleration is 40 m/s²

STEP 3: To find distance travelled

$s = ut + \frac{1}{2} a {t}^{2} \\ \\ s = (0 \times 5) + ( \frac{1}{2} \times 40 \times {(5)}^{2} ) \\ \\ s = 0 + ( \frac{1}{2} \times 40 \times 25 ) \\ \\ s = 20 \times 25 \\ \\ s = 500 \: m$

ANSWER:

Distance travelled by the object by the applied force is 500 m.